What is the molarity of a solution 12.5 naoh dissolved in total volume of 625ml?

NaOH = 12.5/molar mass of NaOH = 12.5/39.99 = 0.313

molarity = no.of moles/volume in L = 0.313/0.625 = 0.501 moles/L

If you mean that the 12.5 NaOH is 12.5 grams of NaOH, then your answer and solution are correct. :)

I have to do the problem in this form.

12.5gNaOH/mol * ??/40.0NaOH * 625ml/ 1 * 1L/ 1000mL

Where am I messing uo

The 625 should be in the denominator.

It should be 12.5 g NaOH x (1 mol NaOH/40 g NaOH) x (1/625 mL) x (1000 mL/L) = ?

I see.

No, the 12.5 g shouldn't have any denominator units. The given was only 12.5 g NaOH, and this is the mass of NaOH.
You should write,
[ 12.5 g NaOH * (1 mol NaOH / 40 g NaOH) ] / [ 625 mL * (1 L / 1000 mL) ]
= 0.500 M

Sorry for the late reply. Hope this helps~ `u`

I got it now thanks guys :)

To calculate the molarity of a solution, you need to follow a few steps.

First, you need to determine the number of moles of the solute, in this case, NaOH. To do this, divide the given mass of NaOH (12.5 grams) by the molar mass of NaOH (39.99 g/mol). The molar mass of NaOH is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).

Next, you need to convert the volume of the solution from milliliters to liters. Divide the given volume (625 mL) by 1000 to get the volume in liters.

Finally, calculate the molarity by dividing the number of moles of NaOH by the volume in liters. Divide 0.313 moles by 0.625 liters to get the molarity of the solution, which is 0.501 moles/L.