solve the simultaneous equation
2y=3x-13
5x-6y=23
as on your other post, use what you have. Since 6y = 3(2y),
5x-3(3x-13)=23
2y=3x-13 5x-6y=23 6y=3(2y) 5x-3(3x-13)=23 5x-9x+39=23 -4x=23-39 -4x=-16 x=4
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To solve the simultaneous equations:
1. Start by rearranging the first equation to solve for y:
2y = 3x - 13
Divide both sides by 2:
y = (3x - 13) / 2
2. Substitute this expression for y in the second equation:
5x - 6((3x - 13) / 2) = 23
3. Simplify the equation:
5x - 3(3x - 13) = 23
5x - 9x + 39 = 23
-4x + 39 = 23
4. Move the constant term to the other side:
-4x = 23 - 39
-4x = -16
5. Divide both sides by -4 to solve for x:
x = (-16) / (-4)
x = 4
6. Substitute the value of x back into either of the original equations to solve for y. Let's use the first equation:
2y = 3(4) - 13
2y = 12 - 13
2y = -1
Divide both sides by 2:
y = -1/2
So the solutions to the simultaneous equations are:
x = 4
y = -1/2
2y=3x-13
5x-6y=23
26-2y
Solve the simultaneous equation
2y-3x=13
3y+x=3