a flask contain 25 ml of HNO3 solution which requires 30 ml of 0.2 M KOH to complete the reaction. calculate the concentration of KOH.
HNO3+ KOH= H2O + KNO3
HNO3+ KOH= H2O + KNO3
mols KOH = M x L = ?
mols HNO3 = mols KOH because of the 1:1 ratio in the balanced equation.
Then M HNO3 = mols HNO3/L HNO3. You know mols and L, solve for M.
To calculate the concentration of KOH, you need to use the concept of stoichiometry and the given information about the volumes and concentration of both solutions involved in the reaction.
Given:
Volume of HNO3 solution = 25 ml
Volume of KOH solution = 30 ml
Concentration of KOH = ?
First, let's convert the volume of KOH solution from milliliters (ml) to liters (L), which will make it easier to work with:
Volume of KOH solution = 30 ml = 30/1000 L = 0.03 L
Next, we need to determine the ratio of moles of HNO3 to KOH in the balanced chemical equation. According to the balanced equation:
1 mole of HNO3 reacts with 1 mole of KOH.
Since the volume of HNO3 solution is not given, we cannot calculate the moles of HNO3 directly. However, since the ratio of moles is 1:1, we can assume that the moles of HNO3 and KOH are equal.
Therefore, the moles of KOH can be calculated using the concentration and volume of KOH solution:
Moles of KOH = Concentration of KOH × Volume of KOH solution
= Concentration of KOH × 0.03 L
Now, we have the moles of KOH. To calculate the concentration of KOH, we need to divide the moles of KOH by the volume of HNO3 solution:
Concentration of KOH = Moles of KOH / Volume of HNO3 solution
Since the moles of KOH and HNO3 are equal (as discussed earlier) and the volume of HNO3 solution is given as 25 ml:
Concentration of KOH = Moles of KOH / 0.025 L
To calculate the concentration, you need to know the moles of KOH. Unfortunately, without additional information, it is not possible to determine the concentration of KOH accurately.