Solve: 2a-3/a+1 = 3a-5/a+3

I have this strange feeling you meant:

(2a-3)/(a+1) = (3a-5)/(a+3)
then
3a^2 -2a - 5 = 2a^2 + 3a - 9

a^2 - 5a + 4 = 0
(a-1)(a-4) = 0
a = 1 or a = 4