To the nearest tenth, what is the distance between (7,4) and (12,5)?
a) 4.8 units
b) 4.9 units
C) 5.0 units
d) 5.1 units
Please explain. Thank you.
The squared distance is sum of squares of difference of all coordinates.
d^2 = (x1-x2)^2 + (y1-y2)^2 = (7-12)^2 + (4-5)^2, so... ;)
Welcome ;)
The answer was about 5.1 by the way.
To find the distance between two points in a coordinate plane, you can use the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the two points are (7, 4) and (12, 5).
Let's calculate the distance using the distance formula:
Distance = √((12 - 7)^2 + (5 - 4)^2)
Simplifying, we have:
Distance = √(5^2 + 1^2)
Distance = √(25 + 1)
Distance = √26
Approximating √26 to the nearest tenth, the distance is approximately 5.1 units.
Therefore, the correct answer is option d) 5.1 units.