A 1-kg ball initially moving with a speed of 3m/s strikes a stationary 2kg ball head-on. After the collision both balls stick together. What are the final velocities of the two balls?
momentum must be conserved:
1*3 + 2*0 = (1+2)v
Although, I fail to see how they could properly roll, if sticking together after such a collision.
4.5
To find the final velocities of the two balls after the collision, we can use the principle of conservation of linear momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The momentum (p) of an object is given by the product of its mass (m) and velocity (v). Mathematically, p = m * v.
Given:
Mass of the first ball (m1) = 1 kg
Initial velocity of the first ball (v1) = 3 m/s
Mass of the second ball (m2) = 2 kg
Initial velocity of the second ball (v2) = 0 m/s (since it is stationary)
Let the final velocity of the combined balls be V.
Using the principle of conservation of momentum:
Initial momentum = Final momentum
(m1 * v1) + (m2 * v2) = (m1 + m2) * V
Substituting the given values:
(1 kg * 3 m/s) + (2 kg * 0 m/s) = (1 kg + 2 kg) * V
3 kg⋅m/s = 3 kg⋅V
Dividing both sides of the equation by 3 kg:
V = 1 m/s
Therefore, the final velocity of the combined balls after the collision is 1 m/s. Since the balls stick together, both balls have the same final velocity of 1 m/s.