Adam wants to compare the fraction 2/5 1/6 and 1/3 he wants to order them from least to greastest and rewrite them so they all have the same denominator explain how Adam can rewrite the fraction

What is the smallest number that is divisible by 5, 6, and 3?

ref to the question above to rewrite 2/5, 1/6 and 1/3 in ascending order : I think we first find the common denominator which is 30 then 2/5 is the simplified fraction of 12/30, 1/6 is also the simplified fraction of 5/30 and lastly10/30 has been simplified to get 1/3. from there we then arrange starting with 5/30, 10/30 , 12/30

To compare the fractions 2/5, 1/6, and 1/3, Adam needs to rewrite them with the same denominator. This will make it easier to determine which fraction is smaller or larger.

To find a common denominator for these three fractions, Adam can follow these steps:

Step 1: Identify the denominators of the fractions: 5, 6, and 3.

Step 2: Find the least common multiple (LCM) of these three denominators. The LCM is the smallest number that all the denominators divide evenly into.

To find the LCM of 5, 6, and 3, Adam can find the prime factors of each number:

5: Prime factor = 5
6: Prime factors = 2 x 3
3: Prime factor = 3

Now Adam can identify the LCM by taking the highest powers of the prime factors involved:

LCM = 2 x 3 x 5 = 30

So, the least common denominator (LCD) for these fractions is 30.

Now, Adam can rewrite each fraction with the denominator of 30:

2/5 = (2 x 6)/(5 x 6) = 12/30
1/6 = (1 x 5)/(6 x 5) = 5/30
1/3 = (1 x 10)/(3 x 10) = 10/30

Now, the fractions 2/5, 1/6, and 1/3 are all rewritten with the same denominator of 30.

Adam can then order the fractions from least to greatest based on their numerators while keeping the denominator constant:

5/30, 10/30, 12/30

Therefore, the fractions, from least to greatest, are 5/30, 10/30, and 12/30.