the rate of diffusion of a gas having molecular weight just double of hydrogen gas is 30 ml/s.the rate of diffusion of hydrogen gas will be
To find the rate of diffusion of hydrogen gas, we can use Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
The formula for Graham's law of diffusion is as follows:
Rate₁/Rate₂ = √(MolarMass₂/MolarMass₁)
Let's denote the rate of diffusion of the gas with double the molecular weight of hydrogen gas as Rate₂ and the rate of diffusion of hydrogen gas as Rate₁.
The molecular weight of hydrogen gas is approximately 2 g/mol.
Plugging in the values into the formula, we have:
Rate₁/Rate₂ = √(MolarMass₂/MolarMass₁)
Rate₁/30 ml/s = √(2 g/mol)/(2 g/mol)
Rate₁/30 ml/s = √1
Rate₁/30 ml/s = 1
To find the value of Rate₁, multiply both sides of the equation by 30 ml/s:
Rate₁ = 30 ml/s
Therefore, the rate of diffusion of hydrogen gas will be 30 ml/s.
(rateH2/rateun) = sqrt(M un/M H2)
Substitute ad solve for rate H2.
un is unknown which I assume is He.