The position of a body moving along x-axis at Time t is given by x=(t^2-4t+6)m. The distance travelled by body in time interval t=0 to t=3s.
the distance is asked which is displacement on every second add them up to get ans=5m
Yes 5m is the answer
To find the distance travelled by the body in the time interval from t = 0 to t = 3s, we need to calculate the total distance covered by the body during this time.
The position equation of the body is given as x = t^2 - 4t + 6 meters.
To find the distance, we need to consider the absolute value of the position function because distance is always positive. So, we will take the absolute value of the position function.
Step 1: Replace t with 3 in the position equation:
x = (3^2) - 4(3) + 6
x = 9 - 12 + 6
x = 3 meters
Step 2: Take the absolute value of x:
|x| = |3|
|x| = 3 meters
Therefore, the distance travelled by the body in the time interval from t = 0 to t = 3s is 3 meters.
Chutiye
When t = 0,
X = 0-0 +6 = 6 m.
When t = 3 s.,
X = 3^2 - 4*3 + 6 = 3 m.
d = 6-3 = 3 m.