How many grams of sucrose (C12H22O11) are in 2.50L of 0.710M sucrose solution?
mols = M x L = ?
Then grams = mols x molar mass
To find the number of grams of sucrose in 2.50L of 0.710M sucrose solution, we need to use the formula:
grams of solute = (volume of solution in liters) x (molarity) x (molar mass of sucrose)
First, we need to find the molar mass of sucrose (C12H22O11). The molar mass can be calculated by adding up the atomic masses of each element present in the molecule.
C: 12.01 g/mol
H: 1.01 g/mol
O: 16.00 g/mol
Molar mass of sucrose = (12.01 x 12) + (1.01 x 22) + (16.00 x 11) = 342.34 g/mol
Now, we can use the formula to find the grams of sucrose:
grams of sucrose = (2.50L) x (0.710M) x (342.34 g/mol)
Calculating this expression will give us the final answer.