If one pound (454g) of hexane combusts how many grams of water are produced?
How do u set this up? Start it?
See your hexane/CO2 post below. Same kind of problem.
My work: 454 g C6H14 * 1 Mol C6H14/86 g C6H14 * 7H20/1 mol C6H14 * 18 g O2/ 1 MOL H2O = 665.2 grams of H2O
To determine the number of grams of water produced when one pound (454g) of hexane combusts, we need to set up and solve a stoichiometry problem.
Step 1: Write down the balanced chemical equation for the combustion of hexane.
The balanced equation for the combustion of hexane is:
C6H14 + 19/2 O2 -> 6 CO2 + 7 H2O
This equation tells us that one molecule of hexane (C6H14) reacts with 19/2 molecules of oxygen (O2) to produce 6 molecules of carbon dioxide (CO2) and 7 molecules of water (H2O).
Step 2: Convert grams of hexane to moles.
Given that we have 454 grams of hexane, we need to convert this to moles. The molar mass of hexane (C6H14) is 12.01*6 + 1.01*14 = 86.18 g/mol. Therefore, 454 g of hexane is equal to 454 g / 86.18 g/mol = 5.27 moles of hexane.
Step 3: Use the stoichiometry of the balanced equation to determine moles of water produced.
By examining the balanced equation, we see that for every 1 mole of hexane combusted, 7 moles of water are produced. Since we have 5.27 moles of hexane, we can set up the following ratio:
5.27 moles hexane : ? moles water
1 mole hexane : 7 moles water
Cross-multiplying and solving for the unknown moles of water, we get:
? moles water = 5.27 moles hexane * (7 moles water / 1 mole hexane) = 36.89 moles water.
Step 4: Convert moles of water to grams.
Lastly, we convert moles of water to grams using the molar mass of water (H2O), which is 18.02 g/mol. Therefore, 36.89 moles of water is equal to 36.89 moles * 18.02 g/mol = 665.05 grams of water.
Therefore, if one pound (454g) of hexane combusts, approximately 665.05 grams of water are produced.