I'm not sure how to answer this:

3. THe 7th grade wants to have a back-up representative just in case the first teacher is absent. Based on the same scenario as #2, if a math teacher was chosen to be the 7th grade representative, what is the probablility that the back-up drawn second will be a different math teacher?
Ans: 2/11 = .18 = 18%

Here's #2 referenced above - There are 3 math teachers, 2 science teachers, 2 social studies teachers, 3 english teachers, and 2 reading teachers. If a teacher is chosen at random to be the 7th grade representative, what is the probability that the teacher will be a math teacher. Ans: 3/12 = 1/4 = .25 = 25%

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To answer the question, we need to understand the total number of possible outcomes and the number of favorable outcomes.

In the given scenario, there are initially 12 teachers in total: 3 math teachers, 2 science teachers, 2 social studies teachers, 3 English teachers, and 2 reading teachers.

If a math teacher is chosen as the 7th grade representative, there are now 11 teachers left: 2 science teachers, 2 social studies teachers, 3 English teachers, and 2 reading teachers.

We want to calculate the probability that the backup teacher drawn second will be a different math teacher, given that a math teacher was chosen as the first representative.

The total number of possible outcomes when drawing the backup teacher second is 11 because there are 11 teachers remaining.

The number of favorable outcomes is 10 because out of the remaining 11 teachers, 1 is a math teacher (the math teacher who was not chosen as the first representative) and 10 are non-math teachers.

Therefore, the probability of drawing a different math teacher as the backup teacher is 10/11.

By simplifying the fraction, we get 2/11.

Converting the fraction to a decimal, we get 0.18.

Converting the decimal to a percentage, we get 18%.

So, the probability that the backup teacher drawn second will be a different math teacher is 18%.