two poles of height 25 metre and 20 metre stand upright in a field. The distance between the poles is 12 metre. Find the distance between their tops
the difference in heights is 5, so the distance between the tops is the hypotenuse of a 5-12-13 right triangle.
i don't know please ask some one else
To find the distance between the tops of the poles, you can use the Pythagorean theorem. This theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In this scenario, the poles and the distance between them form a right-angled triangle, with the height of the shorter pole (20 meters) representing one side, the height of the taller pole (25 meters) representing the other side, and the distance between the poles (12 meters) representing the hypotenuse.
First, square the lengths of both sides:
20^2 = 400
25^2 = 625
Then, add the squares of the two sides:
400 + 625 = 1025
Finally, find the square root of the sum to get the length of the hypotenuse (distance between the tops of the poles):
√1025 ≈ 32.02 meters
Therefore, the distance between the tops of the poles is approximately 32.02 meters.