What is the momentum of a two-particle sys- tem composed of a 1300 kg car moving east at 60 m/s and a second 1500 kg car moving west at 95 m/s? Let east be the positive direction.
Answer in units of kg · m/s.
it's just
∑mv for all the various m and v:
1300(60) + 1500(-95)
To find the momentum of a two-particle system, we need to calculate the momentum of each particle separately and then add them together.
The momentum of an object is calculated by multiplying its mass by its velocity.
For the first car moving east:
Mass (m1) = 1300 kg
Velocity (v1) = 60 m/s
Momentum of the first car (p1) = m1 * v1
p1 = 1300 kg * 60 m/s
For the second car moving west:
Mass (m2) = 1500 kg
Velocity (v2) = -95 m/s (since west is the negative direction)
Momentum of the second car (p2) = m2 * v2
p2 = 1500 kg * (-95 m/s)
Now, let's add the two momenta together:
Total momentum = p1 + p2
Total momentum = (1300 kg * 60 m/s) + (1500 kg * (-95 m/s))
Calculating the values:
p1 = 78000 kg·m/s
p2 = -142500 kg·m/s
Total momentum = 78000 kg·m/s - 142500 kg·m/s
Total momentum = -64500 kg·m/s
Therefore, the momentum of the two-particle system is -64500 kg·m/s.
To find the momentum of a two-particle system, you need to calculate the momentum of each particle separately and then add them together.
The momentum of an object is given by the product of its mass and velocity. Mathematically, it is represented as:
Momentum = mass × velocity
Given:
Mass of the first car (m1) = 1300 kg
Velocity of the first car (v1) = 60 m/s (east)
Momentum of the first car = m1 × v1
Momentum of the first car = 1300 kg × 60 m/s
Now, due to the east being considered the positive direction, the velocity of the second car (v2) will be negative because it is moving west.
Mass of the second car (m2) = 1500 kg
Velocity of the second car (v2) = -95 m/s (west)
Momentum of the second car = m2 × v2
Momentum of the second car = 1500 kg × (-95 m/s)
Now, to find the momentum of the two-particle system, we add the individual momenta together:
Total momentum of the system = Momentum of the first car + Momentum of the second car
So, the momentum of the two-particle system is:
Total momentum = (1300 kg × 60 m/s) + (1500 kg × -95 m/s)
Calculating the equation:
Total momentum = 78,000 kg·m/s + (-142,500 kg·m/s)
Total momentum ≈ -64,500 kg·m/s
Therefore, the momentum of the two-particle system composed of a 1300 kg car moving east at 60 m/s and a second 1500 kg car moving west at 95 m/s is approximately -64,500 kg·m/s.