The steel I-beam in the drawing has a weight of 1.75 × 103 N and is being lifted at a constant velocity. The angles are at 70 degrees. What is the tension in each cable attached to its ends?
To determine the tension in each cable attached to the ends of the steel I-beam, we can make use of the fact that the weight of the beam is balanced by the tension in the cables.
Since the I-beam is being lifted at a constant velocity, we know that the net force acting on it is zero (since it is not accelerating). Therefore, the tension in each cable must be equal to half of the weight of the I-beam.
To calculate the tension in each cable, we can follow these steps:
Step 1: Calculate the weight of the I-beam.
Given that the weight of the I-beam is 1.75 × 10^3 N.
Step 2: Divide the weight of the I-beam by 2 to get the tension in each cable.
Tension in each cable = (Weight of I-beam) / 2
Substituting the given weight of the I-beam:
Tension in each cable = (1.75 × 10^3 N) / 2
Performing the calculation:
Tension in each cable = 875 N
Therefore, the tension in each cable attached to the ends of the I-beam is 875 N.
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