You drop a rock from a 300-meter cliff. How long will it take to reach the ground? Assume it has no significant air resistance

hf=hi-1/2 g t^2

-300=-4.9 t^2
solve for time t.

To determine the time it will take for the rock to reach the ground, we can use the equation for free-fall motion:

s = (1/2)gt^2

Where:
s = distance or height
g = acceleration due to gravity (approximately 9.8 m/s² on Earth)
t = time

In this case, the initial height (s) is 300 meters, and we want to find the time it takes to reach the ground (t). Rearranging the equation to solve for time, we get:

t = sqrt(2s/g)

Substituting the given values, we have:

t = sqrt(2 * 300 / 9.8)
t ≈ sqrt(61.22)

Calculating the square root, we find that t ≈ 7.82 seconds.

Therefore, it will take approximately 7.82 seconds for the rock to reach the ground when dropped from a 300-meter cliff, assuming no significant air resistance.

6.89 seconds?