A solid of relative density 1.25 is found to weigh 12g in water find its weight in air
To find the weight of the solid in air, we need to use the concept of buoyancy.
The buoyant force acting on an object submerged in a fluid (such as water) is equal to the weight of the fluid displaced by the object. According to Archimedes' principle, the buoyant force is directed upward and is equal in magnitude to the weight of the fluid displaced.
Here are the steps to find the weight of the solid in air:
Step 1: Find the weight of the water displaced by the solid.
- The relative density of a substance is defined as the ratio of its density to the density of a reference substance (usually water).
- In this case, the relative density of the solid is 1.25, which means its density is 1.25 times the density of water.
- We already know that the solid weighs 12g in water. This weight is equal to the weight of the water displaced by the solid.
- So, the weight of the water displaced by the solid is also 12g.
Step 2: Find the weight of the solid in water.
- The weight of the solid in water is equal to the weight of the solid minus the weight of the water displaced.
- Since the weight of the solid in water is 12g and the weight of the water displaced is 12g, the weight of the solid is 12g + 12g = 24g in water.
Step 3: Find the weight of the solid in air.
- The weight of the solid in air is equal to the weight of the solid in water plus the weight of the water displaced.
- In this case, the weight of the water displaced is 12g, so the weight of the solid in air is 24g + 12g = 36g.
Therefore, the weight of the solid in air is 36g.