The arrow is spun several times until it stops at a number 4.
Find the probability that this happens on the third spin.
Lacking data.
How many numbers are there?
The probability of hitting a particular number is the same no matter which spin it is.
To find the probability that the arrow stops at number 4 on the third spin, we need to know the total number of possible outcomes and the number of favorable outcomes.
Let's assume that the arrow can stop at any number from 1 to 8 (inclusive).
Total number of possible outcomes: 8 (since the arrow can stop at 8 different numbers)
Favorable outcome(s): 1 (the arrow stops at number 4)
Therefore, the probability of the arrow stopping at number 4 on the third spin is 1 out of 8, which can be expressed as 1/8 or 0.125.
To find the probability that the arrow stops at a particular number on the third spin, we need to know the total number of possible outcomes and the number of favorable outcomes.
Let's consider the possible outcomes first. If the arrow can stop at any number from 1 to 4, then there are four possible outcomes on each spin.
On the first spin, there are four possible outcomes: 1, 2, 3, or 4.
On the second spin, there are also four possible outcomes: 1, 2, 3, or 4.
On the third spin, there are also four possible outcomes: 1, 2, 3, or 4.
Since the arrow can stop at any number on each spin, the total number of possible outcomes for all three spins is 4 * 4 * 4 = 64.
Now let's consider the favorable outcomes. We want the arrow to stop at the number 4 on the third spin. The first two spins don't matter in this case; we just need the arrow to stop at 4 on the third spin. So there is only one favorable outcome.
Therefore, the probability that the arrow stops at the number 4 on the third spin is 1 favorable outcome out of 64 possible outcomes, which can be written as 1/64.
To summarize:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 1 / 64