How do I determine the quantity (g) of pure MgSO4 in 2.4g of MgSO4.7H2O

%MgSO4 in MgSO4.7H2O = [(molar mass MgSO4/molar mass MgSO4.7H2O)]*100 = ?

Then 2.4g x (%MgSO4/100) = ?

THANK YOU! That's what I needed!!

To determine the quantity of pure MgSO4 in 2.4g of MgSO4.7H2O, you need to consider the molar mass and the percent composition of the compound.

Step 1: Calculate the molar mass of MgSO4.7H2O.
- The molar mass of MgSO4 is:
- Mg: 24.31 g/mol
- S: 32.06 g/mol
- O (x4): 16.00 g/mol = 64.00 g/mol
- The molar mass of H2O is:
- H (x2): 1.01 g/mol = 2.02 g/mol
- O: 16.00 g/mol
- Total: 18.02 g/mol
- The molar mass of MgSO4.7H2O is the sum of MgSO4 and 7H2O:
- MgSO4: 24.31 + 32.06 + 64.00 = 120.37 g/mol
- 7H2O: (7 * 18.02) = 126.14 g/mol
- Total: 120.37 + 126.14 = 246.51 g/mol

Step 2: Determine the percent composition of MgSO4 in MgSO4.7H2O.
- The percent composition of MgSO4 is:
- Mg: (24.31 / 246.51) * 100 = 9.87%
- S: (32.06 / 246.51) * 100 = 13.01%
- O (x4): (64.00 / 246.51) * 100 = 25.97%
- The percent composition of MgSO4 in MgSO4.7H2O is:
- MgSO4: (9.87 + 13.01 + 25.97) = 48.85%

Step 3: Calculate the quantity of pure MgSO4.
- Multiply the percent composition of MgSO4 by the mass of MgSO4.7H2O:
- Quantity of pure MgSO4 = (48.85 / 100) * 2.4 g
- Quantity of pure MgSO4 = 1.17 g

Therefore, the quantity of pure MgSO4 in 2.4g of MgSO4.7H2O is 1.17g.

To determine the quantity of pure MgSO4 in 2.4g of MgSO4.7H2O, you need to consider the molecular weight and stoichiometry of the compound. Here's how you can calculate it:

1. Determine the molecular weight of MgSO4.7H2O:
- The atomic mass of magnesium (Mg) is 24.31 g/mol.
- The atomic mass of sulfur (S) is 32.07 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
- The atomic mass of hydrogen (H) is 1.01 g/mol.
- Since there are seven water (H2O) molecules present, multiply the atomic mass of water by 7.
- Calculate the molecular weight of MgSO4.7H2O by adding up the atomic masses:
(24.31 g/mol × 1) + (32.07 g/mol × 1) + (16.00 g/mol × 4) + (1.01 g/mol × 2 × 7) = 246.47 g/mol.

2. Determine the ratio of pure MgSO4 to MgSO4.7H2O:
- In each MgSO4.7H2O molecule, there is one MgSO4. Therefore, the ratio is 1:1.

3. Calculate the quantity of pure MgSO4:
- To calculate the quantity of pure MgSO4, multiply the ratio by the mass of MgSO4.7H2O:
(1/1) × 2.4 g = 2.4 g.

Therefore, the quantity of pure MgSO4 in 2.4g of MgSO4.7H2O is 2.4 grams.