If you dissolve 3.5 moles of CaCl2 in a solution, how many moles of C+2 ions and C- ions will there be in the solution?

I assume you made a typo. Technically there will not be any C+2 nor any C- ions.

There is 1 mol Ca ion in 1 mol CaCl2 and 2 mols Cl^- in a mol of CaCl2. So if you start with 3.5 mols CaCl2 you will have 3.5 mols Ca^2+ and 7 mols Cl^-

To determine the number of moles of C+2 ions and C- ions present in the solution when 3.5 moles of CaCl2 are dissolved, we need to understand the chemical formula of calcium chloride (CaCl2) and its dissociation in water.

The formula for calcium chloride (CaCl2) suggests that for every formula unit of CaCl2, there is one Ca2+ ion and two Cl- ions. This means that one formula unit of CaCl2 can produce one mole of Ca2+ ions and two moles of Cl- ions.

Given that you have 3.5 moles of CaCl2, we can determine the number of moles of C+2 ions and C- ions as follows:

Number of moles of C+2 ions = Number of moles of calcium ions (Ca2+) = Number of moles of CaCl2

Number of moles of C+2 ions = 3.5 moles

Number of moles of C- ions = 2 × Number of moles of chloride ions (Cl-) = 2 × Number of moles of CaCl2

Number of moles of C- ions = 2 × 3.5 moles = 7 moles

Therefore, when 3.5 moles of CaCl2 are dissolved, there will be 3.5 moles of C+2 ions and 7 moles of C- ions in the solution.

To answer this question, we need to understand the chemical formula for calcium chloride (CaCl2) and break it down into its constituent ions.

Calcium chloride consists of one calcium ion (Ca2+, cation) and two chloride ions (Cl-, anions). When it dissolves in water, it dissociates into these ions.

Given that you've dissolved 3.5 moles of CaCl2 in solution, we can determine the number of moles of ions present.

For every mole of CaCl2, there is one mole of Ca2+ and two moles of Cl- ions. So if you have 3.5 moles of CaCl2, you will have:

Number of moles of Ca2+ ions = 3.5 moles
Number of moles of Cl- ions = 3.5 moles * 2 = 7 moles

Therefore, in the solution, there will be 3.5 moles of Ca2+ ions and 7 moles of Cl- ions.