A 1,280-kg car pulls a 350-kg trailer. The car exerts a horizontal force of 3,600-N against the ground in order to accelerate. What force does the car exert on the trailer? Assume an effective friction coefficient of 0.15 for the trailer.
acceleration=3600/(1280+350)
solve for acceleration
now, the trailer.
Net force=pulling-friction=mass*a
pulling force=350*a+350*g*mu
solve for pulling force.
mu is the friction coefficient. Upstairs anon is also wrong on how to solve it
This doesn’t help at all👌
Thxx, finally understand
To find the force that the car exerts on the trailer, we need to consider the net force acting on the car-trailer system.
Let's break down the forces acting on the car:
1. The force applied by the car against the ground: 3,600 N
2. The force of friction between the tires of the car and the ground: This force opposes the motion of the car and can be calculated using the formula:
Friction Force = (friction coefficient) × (normal force)
Since the car and the trailer are connected, the normal force acting on the car is equal to the weight of the entire system (car + trailer):
Normal Force = (mass of car + mass of trailer) × (acceleration due to gravity)
In this case, the normal force acting on the car is:
Normal Force = (1,280 kg + 350 kg) × (9.8 m/s^2) = 16,450 N
Given that the effective friction coefficient is 0.15, the friction force is:
Friction Force = 0.15 × 16,450 N = 2,468 N
Now, let's determine the net force acting on the system:
Net Force = Applied Force - Friction Force
= 3,600 N - 2,468 N
= 1,132 N
Since the car and trailer are connected, the net force acting on them is the same. Therefore, the force that the car exerts on the trailer is 1,132 N.