Solve the equation
(3x-1)(x-5)=-11
(3x-1)(x-5) = -11
3x^2 - 16x + 5 = -11
3x^2 - 16x - 16 = 0
(3x-4)(x-4) = 0
Now you can find x. If two numbers multiply to zero, one or the other must be zero! So,
x = 4/3 or x = 4
(3x-1)(x-5)=-11
3x^2 - 16x + 5 = -11
3x^2 - 16x - 16 = 0
(3x-4)(x-4) = 0
Now you can find x. If two numbers multiply to zero, one or the other must be zero! So,
x = 4/3 or x = 4