in a spin circle are numbers 10, 2, 4,6, 2, 8, what is the probability of spinning a 2 at first spin.

In circle spin with numbers 2,4,6,2,8,10, what is the probability of spin a 2 at the first spit.

there are two 2's and 6 possible stopping places.

So, P(2) = 2/6

To find the probability of spinning a 2 at the first spin in a spin circle, we need to calculate the number of favorable outcomes (spinning a 2) divided by the total number of possible outcomes.

First, let's count the number of favorable outcomes. From the given numbers (10, 2, 4, 6, 2, 8), there are two instances of the number 2.

Next, let's determine the total number of possible outcomes. In this case, we have a spin circle with 6 numbers (10, 2, 4, 6, 2, 8), so there are a total of 6 possible outcomes.

Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:

Probability of spinning a 2 at the first spin = Number of favorable outcomes / Total number of possible outcomes
Probability of spinning a 2 at the first spin = 2 / 6

Simplifying the fraction, we get:

Probability of spinning a 2 at the first spin = 1 / 3

Therefore, the probability of spinning a 2 at the first spin is 1/3, or approximately 0.33.