Larry mows the same-sized lawns in his neighborhood each weekend during the summer.
Part A
Each time Larry mows a lawn he uses 1/6 of a gallon of gasoline. If he has 2/3 of a gallon of gasoline, how many lawns can he mow before he needs to buy more gasoline? Show your work.
Part B
Larry's gasoline container holds 3.5 gallons of gasoline. If gasoline costs $2.25 per gallon, and Larry fills the container, how much change will Liam get back if he pays for the gasoline with a $10 bill? Show your work.
Part C
Larry says he can mow 3 lawns in 5 hours. At this same rate, how many lawns can he mow in 40 hours? Show your work.
A
(2/3) / (1/6)
(2/3) * 6 = 12/3 = 4 lawns
B
10 - (3.5 * 2.25) = ?
C
3/5 = x/40
Thank you !!!
You're welcome.
Part A:
To find out how many lawns Larry can mow before he needs to buy more gasoline, we need to divide the amount of gasoline he has (2/3 of a gallon) by the amount of gasoline he uses to mow one lawn (1/6 of a gallon).
So the calculation is: (2/3) ÷ (1/6).
To divide fractions, we need to multiply the first fraction by the reciprocal of the second fraction:
(2/3) ÷ (1/6) = (2/3) × (6/1) = (2 × 6) / (3 × 1) = 12/3 = 4.
Therefore, Larry can mow 4 lawns before he needs to buy more gasoline.
Part B:
To calculate the total cost for filling Larry's gasoline container, we need to multiply the number of gallons (3.5) by the cost per gallon ($2.25).
So the calculation is: 3.5 × $2.25.
Multiplying these numbers gives us: $7.875.
Therefore, the total cost of filling Larry's gasoline container is $7.875. If he pays with a $10 bill, the change he will get back is: $10 - $7.875 = $2.125.
Part C:
To find out how many lawns Larry can mow in 40 hours at the same rate of mowing 3 lawns in 5 hours, we can set up a proportion:
3 lawns / 5 hours = x lawns / 40 hours.
To solve for x, we can cross-multiply:
(3 * 40) = (5 * x).
120 = 5x.
Dividing both sides of the equation by 5 gives us:
120 / 5 = x.
x = 24.
Therefore, Larry can mow 24 lawns in 40 hours at the same rate.