A horizontal force of 24 N is being applied to a box on a level surface. The box is accelerating at the rate of2280889against a frictional force of 14 N. What is the mass of the box?

Fap = 24 N. = Force applied.

a = 2.28 m/s^2?
Fk = 14 N.

(Fap-Fk) = M*a
M = (Fap-Fk)/a = (24-14)/2.28 = 4.39 kg.
= Mass of the box.

To determine the mass of the box, we need to use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

According to the problem, a horizontal force of 24 N is being applied to the box, and it is accelerating at a rate of 2.28 m/s^2 against a frictional force of 14 N. Let's denote the mass of the box as 'm'.

The force acting on the box is the applied force minus the frictional force:

Force = Applied force - Frictional force
= 24 N - 14 N
= 10 N

Now, according to Newton's second law, the force acting on the box is equal to the mass of the box multiplied by its acceleration:

Force = mass × acceleration
10 N = m × 2.28 m/s^2

To find the mass 'm', we need to rearrange the equation:

m = Force / acceleration
= 10 N / 2.28 m/s^2
≈ 4.38 kg

Therefore, the mass of the box is approximately 4.38 kg.

To find the mass of the box, we can use Newton's second law of motion, which states that the net force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a):

F = m * a

Given:
Force (F) = 24 N (applied force)
Frictional force (f) = 14 N
Acceleration (a) = 2.280889 m/s^2

We can subtract the frictional force from the applied force to find the net force:

Net force = 24 N - 14 N
Net force = 10 N

Now, we can rearrange the equation to solve for the mass (m):

m = F / a

Substituting the values:

m = 10 N / 2.280889 m/s^2
m ≈ 4.38 kg

Therefore, the mass of the box is approximately 4.38 kg.