How many moles of methane gas, CH 4 , are in a 1.00×103L storage tank at STP?
PV = nRT
44.6
To find the number of moles of methane gas in a storage tank at STP (Standard Temperature and Pressure), you can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (atmospheres)
V = volume (liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (Kelvin)
At STP, the pressure is 1 atmosphere and the temperature is 273.15 Kelvin. We are given the volume of the storage tank, which is 1.00×10^3 L.
Let's plug in the values into the equation:
(1 atm) x (1.00×10^3 L) = n x (0.0821 L·atm/(mol·K)) x (273.15 K)
Simplifying the equation:
1000 atm·L = n x 22.414 L·atm/mol
Dividing both sides of the equation by 22.414:
n = 1000 atm·L / 22.414 L·atm/mol
n ≈ 44.66 mol
Therefore, there are approximately 44.66 moles of methane gas in the 1.00×10^3 L storage tank at STP.