Silver nitrate and aluminum chloride react with each other by exchanging anions as shown below.

3 AgNO3 (aq)+ AlCl3 (aq) → Al(NO3)3 (aq) + 3 AgCl (s)
How many moles of AgCl is produced when 1 mol of AgNO3 reacts with 1 mol of AlCl3?

To determine the number of moles of AgCl produced when 1 mol of AgNO3 reacts with 1 mol of AlCl3, we can use the balanced chemical equation:

3 AgNO3 (aq) + AlCl3 (aq) → Al(NO3)3 (aq) + 3 AgCl (s)

From the equation, we can see that the stoichiometric ratio between AgNO3 and AgCl is 3:3. This means that for every 3 moles of AgNO3 reacted, 3 moles of AgCl will be produced.

Since we are given that we have 1 mol of AgNO3 and 1 mol of AlCl3, we can conclude that the reaction will consume 1 mol of AgNO3 and produce an equal amount of AgCl.

Therefore, when 1 mol of AgNO3 reacts with 1 mol of AlCl3, 1 mol of AgCl will be produced.

From the balanced chemical equation:

3 AgNO3 (aq) + AlCl3 (aq) -> Al(NO3)3 (aq) + 3 AgCl (s)

We can see that the mole ratio between AgNO3 and AgCl is 3:3 or 1:1. This means that for every 1 mole of AgNO3, 1 mole of AgCl is produced.

Therefore, when 1 mole of AgNO3 reacts with 1 mole of AlCl3, we would expect 1 mole of AgCl to be produced.

Where are you stuck on this problem. You know to find the limiting reagent.