What volume of 0.050 M AgNO3, silver nitrate solution is required to reat completely with 60.0 mL of 0.025 M K2S, potassium sulfide?
First, we write the balanced reaction:
2 AgNO3 + K2S -> 2 KNO3 + Ag2S
Recall that molarity is moles per liter solution, or
M = n/V
Then we get the number of moles of K2S by simply multiplying the volume (should be in L units) by the concentration (Molarity has units mol/L):
n = V * M
n = 0.060 L * 0.025 M = 0.0015 mol K2S
From the balanced reaction, we get the ratio of AgNO3 and K2S. For every 1 mole of K2S, 2 moles of AgNO3 should be reacted. Therefore, to cancel units,
0.0015 mol K2S * (2 mol AgNO3 / 1 mol K2S) = 0.003 mol AgNO3
Now that we know the moles of AgNO3, to get its volume, we divide the moles by the concentration:
V = n / M
V = 0.003 / 0.05
V = 0.06 L
V = 60 mL AgNO3
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To determine the volume of the silver nitrate (AgNO3) solution required to react completely with the potassium sulfide (K2S) solution, we can use the balanced chemical equation between the two compounds.
The balanced chemical equation between AgNO3 and K2S is:
2 AgNO3 + K2S -> Ag2S + 2 KNO3
From the balanced equation, we can see that 2 moles of AgNO3 react with 1 mole of K2S to produce 1 mole of Ag2S.
To find the volume of AgNO3 solution required, we can use the equation:
(Moles of K2S) / (Molarity of AgNO3) = Volume of AgNO3 solution (in liters)
First, we need to find the number of moles of K2S. We can use the formula:
Moles = Molarity * Volume (in liters)
Given:
Molarity of K2S = 0.025 M
Volume of K2S solution = 60.0 mL = 0.060 L
Moles of K2S = 0.025 M * 0.060 L = 0.0015 moles
Now, using the balanced equation, we know that 1 mole of K2S reacts with 2 moles of AgNO3. Therefore, 0.0015 moles of K2S will react with (2 * 0.0015) = 0.003 moles of AgNO3.
Finally, we can calculate the volume of AgNO3 solution required:
Volume of AgNO3 solution = Moles of K2S / Molarity of AgNO3
Assuming the molarity of AgNO3 is 0.050 M (as given in the question), we can substitute the values into the equation:
Volume of AgNO3 solution = 0.003 moles / 0.050 M = 0.06 L (or 60.0 mL)
Therefore, to completely react with 60.0 mL of 0.025 M K2S solution, we would need 60.0 mL of 0.050 M AgNO3 solution.