What salt results from the neutralization of acetic acid with potassium hydroxide?
We write the reaction:
HC2H3O2 + KOH -> KC2H3O2 + H2O
The products are potassium acetate (salt) and water.
Thank you
The neutralization of acetic acid (CH3COOH) with potassium hydroxide (KOH) results in the formation of a salt known as potassium acetate (CH3COOK).
To determine the salt that results from the neutralization of acetic acid with potassium hydroxide, we need to understand the reaction between the two compounds.
Acetic acid, which has the chemical formula CH3COOH, is a weak acid. When it reacts with potassium hydroxide (KOH), a strong base, a neutralization reaction occurs. The general equation for this reaction is:
CH3COOH + KOH → CH3COOK + H2O
In this reaction, potassium hydroxide (KOH) will donate its hydroxide ion (-OH) to the acetic acid (CH3COOH). This will form potassium acetate (CH3COOK), a salt, and water (H2O).
Therefore, the salt that results from the neutralization of acetic acid with potassium hydroxide is potassium acetate (CH3COOK).