solve
3 square root 2x +1 =3
2x +1 under the sqaure
3 square root( 2 x + 1 ) = 3 square both sides
3 ^ 2 * square root( 2 x + 1 ) ^ 2 = 3 ^ 2
9 * ( 2 x + 1 ) ^ 2 = 9 Divide both sides by 9
2 x + 1 = 1 Subtract 1 to both sides
2 x + 1 - 1 = 1 - 1
2 x = 0 Divide both sides by 2
x = 0