3.05 g of hydrated copper sulfate produce 1.94 g of anhydrous salt. Assuming complete removal of water of crystallisation, determine the formula of hydrated copper sulfate.

To determine the formula of hydrated copper sulfate, we need to analyze the information given and use the concept of molar ratios.

1. We are given that 3.05 g of hydrated copper sulfate produces 1.94 g of anhydrous salt.
2. Anhydrous salt refers to the copper sulfate without any water molecules attached, while hydrated copper sulfate contains water molecules.
3. The difference in mass between the hydrated and anhydrous salt is due to the water of crystallization, which needs to be removed to get the anhydrous form.
4. The water of crystallization is attached to the copper sulfate in a fixed ratio, and by determining this ratio, we can deduce the formula of the hydrated copper sulfate.

Let's calculate the number of moles of both hydrated and anhydrous copper sulfate:

1. Calculate the moles of anhydrous copper sulfate:
- Mass of anhydrous copper sulfate = 1.94 g
- Molar mass of anhydrous copper sulfate (CuSO4) = 159.61 g/mol (63.55 g/mol for Cu + 32.06 g/mol for S + 4 * 16.00 g/mol for O)
- Moles of anhydrous copper sulfate = mass / molar mass = 1.94 g / 159.61 g/mol = 0.01215 mol

2. Calculate the moles of hydrated copper sulfate:
- Mass of hydrated copper sulfate = 3.05 g
- Moles of hydrated copper sulfate = mass / molar mass
- Since we don't know the molar mass yet, we need to determine the molar ratio between anhydrous and hydrated copper sulfate using the mass difference.

- Mass difference = mass of hydrated copper sulfate - mass of anhydrous copper sulfate
- Mass difference = 3.05 g - 1.94 g = 1.11 g (This is the mass of water that was removed)
- Water's molar mass (H2O) = 18.02 g/mol (2 * 1.01 g/mol for H + 16.00 g/mol for O)
- Moles of water = mass difference / molar mass of water = 1.11 g / 18.02 g/mol = 0.0615 mol

Now, since 1 mole of hydrated copper sulfate will contain a fixed number of moles of water, we can determine the molar ratio between hydrated copper sulfate and water.
- Moles of hydrated copper sulfate = Moles of water / molar ratio
- By comparing the coefficients in front of CuSO4 and H2O in the balanced equation, we can determine the molar ratio.

Note: The molar ratio will be in whole numbers since we assume that all the water is removed.

Let's solve for the molar ratio:

0.0615 mol of water = Moles of hydrated copper sulfate / molar ratio

By cross-multiplying:

Moles of hydrated copper sulfate = 0.0615 mol * molar ratio

We know that the moles of hydrated copper sulfate are also given by the mass of the compound divided by its molar mass:

Moles of hydrated copper sulfate = 3.05 g / molar mass of hydrated copper sulfate

Equating both expressions for moles of hydrated copper sulfate:

0.0615 mol * molar ratio = 3.05 g / molar mass of hydrated copper sulfate

Now, we need to rearrange this equation to solve for the molar ratio:

Molar ratio = (3.05 g / molar mass of hydrated copper sulfate) / 0.0615 mol

Now, let's divide the moles of hydrated copper sulfate by the molar ratio and find the formula:

Moles of hydrated copper sulfate / molar ratio = (3.05 g / molar mass of hydrated copper sulfate) / (0.0615 mol / molar ratio)

By cross-multiplying and simplifying:

Molar ratio * molar mass of hydrated copper sulfate = 0.0615 mol * 3.05 g

Finally, we can determine the molar ratio by dividing the moles of water by the molar ratio:

molar ratio = (0.0615 mol * 3.05 g) / molar mass of hydrated copper sulfate

To find the molar ratio:

1. Calculate the molar mass of hydrated copper sulfate: Subtract the mass of water from the mass of the hydrated copper sulfate.
- Molar mass of hydrated copper sulfate = mass of hydrated copper sulfate - mass of water / moles of hydrated copper sulfate
- Molar mass of hydrated copper sulfate = (3.05 g - 1.11 g) / 0.01215 mol = 158.54 g/mol

2. Substitute the molar mass of hydrated copper sulfate back into the equation for the molar ratio:
- Molar ratio = (0.0615 mol * 3.05 g) / (158.54 g/mol)
- Molar ratio = 1.190

Since we assumed there is only one water molecule attached to each copper sulfate molecule, the molar ratio can be approximated as 1. Therefore, the formula for hydrated copper sulfate is CuSO4 ยท H2O.

CuSO4.xH2O ==> CuSO4 + xH2O

g H2O = g hydrate - g salt = 1.11g
mols CuSO4 = grams/molar mass = ?
mols H2O = grams/molar mass = ?

Now find the ratio of mols H2O to mols of 1 mol CuSO4 and round to the nearest whole number.

-0.01MOL OF CUSO4

-0.12MOL OF H20
:FORMULAR IS CUSO4[H20]12

where did you get the mass of water?