The first three terms of a GP are k-3,2k-4,4k-3 in that order .find the valve of k and the first 8 terms
since there is a common ratio,
(2k-4)/(k-3) = (4k-3)/(2k-4)
(2k-4)^2 = (4k-3)(k-3)
4k^2 - 16k + 16 = 4k^2 - 15k + 9
k = 7
Now just plug and chug.