a solution is prepared by dissolving145 grams of NaNO3 in 100 grams of water at 80*C. the solution is then cooled to 10*C. how much of the solute will come out of the solution?
You need to read your solubility chart. http://www.kentchemistry.com/images/links/Kinetics/Solubi1.gif
what is the difference between the 80C and 10 C solubility?
To determine how much solute will come out of the solution when it is cooled, we need to calculate the solubility of NaNO3 at both 80°C and 10°C.
1. Solubility of NaNO3 at 80°C:
We need to find the maximum amount of NaNO3 that can dissolve in 100 grams of water at 80°C. This information can typically be found in a solubility table. Let's assume that the solubility of NaNO3 at 80°C is 200 grams per 100 grams of water.
So, at 80°C, the solution contains 145 grams of NaNO3 dissolved in 100 grams of water. Since the solubility limit is 200 grams, the solution is not saturated, and all of the solute is dissolved.
2. Solubility of NaNO3 at 10°C:
Again, using a solubility table, we find that the solubility of NaNO3 at 10°C is 70 grams per 100 grams of water.
Now, we need to calculate the mass of the solution at 10°C. The original solution had a total mass of 145 grams (solute) + 100 grams (solvent) = 245 grams.
To determine how much solute will come out of the solution, we need to compare the original amount of solute (145 grams) to the solubility limit at 10°C (70 grams per 100 grams of water).
Using a proportion, we can calculate the maximum amount of NaNO3 that can dissolve in the cooled solution:
(145 grams / 200 grams) = (X grams / 245 grams)
Solving for X, we find:
X = (145 grams / 200 grams) * 245 grams
X ≈ 177.63 grams
Therefore, when the solution is cooled to 10°C, approximately 177.63 grams of NaNO3 will precipitate out of the solution, meaning it will no longer remain dissolved.