F:x 2*-1 meaning two to the power ex minus one please help with drawing the graph
can't tell whether you mean
2^x - 1
or
2^(x-1)
In either case, see
http://www.wolframalpha.com/input/?i=plot+2^x-1%2C+2^%28x-1%29
Sorry i mean 2* -1
To draw the graph of the function f(x) = 2^x - 1, you can follow these steps:
1. Determine the domain of the function. Since 2^x is defined for all real numbers, the domain of f(x) is the set of all real numbers (i.e., (-∞, +∞)).
2. Choose a few x-values within the domain and find the corresponding y-values. Using a table of values will help you plot the points and sketch the graph accurately. Let's choose a few arbitrary x-values: x=-2, -1, 0, 1, 2.
For example, when x = -2, we have f(-2) = 2^(-2) - 1 = 1/4 - 1 = -3/4.
Similarly, for x = -1, we have f(-1) = 2^(-1) - 1 = 1/2 - 1 = -1/2.
For x = 0, f(0) = 2^0 - 1 = 1 - 1 = 0.
For x = 1, f(1) = 2^1 - 1 = 2 - 1 = 1.
For x = 2, f(2) = 2^2 - 1 = 4 - 1 = 3.
3. Plot the points from your table of values on a coordinate plane. For example, the points (-2, -3/4), (-1, -1/2), (0, 0), (1, 1), and (2, 3) should be plotted.
4. Determine the behavior of the function as x approaches positive infinity (+∞) and negative infinity (-∞). Since 2^x increases exponentially as x increases, and the -1 term shifts the graph down by 1 unit, the graph of f(x) will approach negative infinity as x approaches -∞ and approach positive infinity as x approaches +∞.
5. Connect the plotted points smoothly, keeping in mind the behavior of the function. The graph should resemble a curve that approaches, but never touches, the x-axis as x approaches +∞.