A body accelerate from rest at (2m/s square) calculate its velocity after travelling 9m
A=2m/s,s=9m,v?,vsquare=usquare +2as, vsquare=2as,vsquare=2 multiply by 2 multiply by 9=36,vsquare=square root of 36, vsquare=6m/s square
V^2 = Vo^2 + 2a*d = 0 + 2*2*9 = 36
V = 6 m/s
answer
To calculate the velocity of an object after traveling a given distance, we can use the kinematic equation:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity (in this case, 0 m/s as it starts from rest)
a = acceleration (2 m/s^2)
s = distance traveled (9 m)
First, let's plug in the values into the equation:
v^2 = 0^2 + 2 * 2 * 9
Simplifying the equation:
v^2 = 0 + 36
v^2 = 36
To find the velocity (v), we take the square root of both sides:
v = √36
v = 6 m/s
Therefore, the velocity of the body after traveling 9 meters is 6 m/s.