A simple wheel and axle is used to life a bucket out of a well. The radii of the wheel and axle are 20 cm and 4 cm, respectively. Determine: 1. The velocity ratio (and so the IMA), 2. The thoretical effort required to life a load of 30 N assuming no energy loosses, 3. The efficincy if the actual effort required is 30 N.

1=5

2=6
3=50%

A simple wheel and axle is used to life bucket of water out of a well the radii of the wheel and axle are 20cm and 4cm respectively determine

I do know the answer pleas tell me

I don't know the answer of the C question please tell me

VR=R/r =20/4 =5 and also IMA

1. Well, well, well, let's calculate the velocity ratio! The velocity ratio is determined by dividing the radius of the wheel by the radius of the axle. In this case, the radius of the wheel is 20 cm and the radius of the axle is 4 cm. So, the velocity ratio is 20 cm / 4 cm, which simplifies to 5. Therefore, the velocity ratio (and IMA) is 5.

2. To find the theoretical effort required, we can use the formula: Effort = Load / IMA. In this case, the given load is 30 N and the IMA is 5. Plugging these values in, we get Effort = 30 N / 5 = 6 N. So, the theoretical effort required to lift a 30 N load is 6 N.

3. Ah, the efficiency! To calculate efficiency, we use the formula: Efficiency = (Actual Effort / Theoretical Effort) x 100%. In this case, the actual effort is given as 30 N and the theoretical effort we just calculated is 6 N. Substituting these values, we get Efficiency = (30 N / 6 N) x 100% = 500%. Well, that's quite an impressive efficiency, but unfortunately, it is higher than 100% which violates the laws of physics! So, there might be some energy losses here or a mistake in the calculation.

To determine the answers for the given scenario, we need to understand the concepts of velocity ratio, ideal mechanical advantage (IMA), theoretical effort, and efficiency.

1. Velocity Ratio and IMA:
The velocity ratio is the ratio of the distance moved by the effort (the force applied to lift the object) to the distance moved by the load (the force being lifted). In this case, the effort is applied to the axle, and the load is attached to the wheel.

The velocity ratio (VR) can be calculated using the formula:
VR = Radius of the wheel ÷ Radius of the axle

VR = 20 cm ÷ 4 cm = 5

The IMA is equal to the velocity ratio when there are no energy losses or frictional forces.

IMA = VR = 5

2. Theoretical Effort:
To calculate the theoretical effort required, we can use the equation:

Theoretical Effort (TE) = Load ÷ IMA

TE = 30 N ÷ 5 = 6 N

Therefore, the theoretical effort required to lift a load of 30 N using this wheel and axle system is 6 N.

3. Efficiency:
Efficiency is a measure of how well a machine converts input work (effort) into output work (load). It is typically expressed as a percentage.

Efficiency = (Output work ÷ Input work) × 100%

In this case, the actual effort required is given as 30 N.

Input work = Actual Effort × Distance moved by the actual effort
Output work = Load × Distance moved by the load

To calculate the efficiency, we need to know the distances moved by the actual effort and load, which are not provided.

However, we can still calculate the efficiency using theoretical values and the efficiency formula:

Efficiency = (Theoretical Effort ÷ Actual Effort) × 100%

Efficiency = (6 N ÷ 30 N) × 100% = 20%

So, the efficiency of the system, assuming the actual effort required is 30 N, is 20%.