The power output in the sun is about 4.00 x 10^26W.

(a). Calculate the power per unit area (intensity), in kilowatts per square meter, reaching Earth's upper atmosphere from the sun. The radius of the Earth's orbit is 1.5 x 10^11m.

Anyone

1.415 kW/m^2 *ftfy

To calculate the power per unit area or intensity of sunlight reaching Earth's upper atmosphere, we can use the inverse square law, which states that the intensity of radiation is inversely proportional to the square of the distance from the source.

First, let's calculate the surface area of the sphere with a radius equal to the distance from the sun to Earth's orbit using the formula:
Surface Area = 4πr^2, where r is the radius of Earth's orbit (1.5 x 10^11 m).

Surface Area = 4π(1.5 x 10^11)^2 = 4π(2.25 x 10^22) = 9π x 10^22 m^2

Now, we can divide the power output of the sun (4.00 x 10^26 W) by the surface area to find the power per unit area:

Power per unit area = Power output / Surface area
Power per unit area = (4.00 x 10^26 W) / (9π x 10^22 m^2)

To convert the answer to kilowatts per square meter (kW/m^2), we need to divide by 1000:

Power per unit area = [(4.00 x 10^26) / (9π x 10^22)] / 1000 kW/m^2

Calculating this expression yields the value of the power per unit area or intensity of sunlight reaching Earth's upper atmosphere from the Sun in kilowatts per square meter.

1415 kW/m^2