Calculate the energy released when 235 U fissions resulting in two lighter stable nuclei with mass numbers 140 and 93.Please help!

To calculate the energy released during nuclear fission, you can use Albert Einstein's famous equation, E = mc^2, where E is the energy released, m is the mass difference, and c is the speed of light.

Here's how you can calculate the energy released when 235U (uranium-235) undergoes fission:

1. Determine the mass difference: Uranium-235 (235U) has a mass of 235 atomic mass units (u). After fission, the two resulting nuclei have mass numbers of 140 and 93. Subtracting these masses from the initial mass will give you the mass difference.

Initial mass = 235 u
Final mass = 140 u + 93 u = 233 u

Mass difference = Initial mass - Final mass = 235 u - 233 u = 2 u

2. Convert the mass difference to kilograms: Since Einstein's equation uses mass in kilograms, we need to convert the mass difference from unified atomic mass units (u) to kilograms (kg). Remember that 1 u is equal to 1.66 x 10^-27 kg.

Mass in kg = Mass difference in u x (1.66 x 10^-27 kg/u)

Mass in kg = 2 u x (1.66 x 10^-27 kg/u) = 3.32 x 10^-27 kg

3. Calculate the energy released: Now, you can use Einstein's equation to find the energy released during fission.

Energy released = Mass in kg x (speed of light)^2

Energy released = (3.32 x 10^-27 kg) x (3 x 10^8 m/s)^2

Energy released = 2.988 x 10^-11 joules

Therefore, the energy released when 235U undergoes fission resulting in two lighter stable nuclei with mass numbers 140 and 93 is approximately 2.988 x 10^-11 joules.