Please help! I have 30 ml bottle of 5% hydrocholric acid. Ned to dillute to make 200 ml of .01 M hydrocholric acid. I don't know how much of the bottle solution to add to how much distilled water to get 200 ml at .01 M
It's all done with
mL1 x M1 = mL2 x M2
Substitute the numbers and you have it.