Perform this operation and report the answer to the correct number of significant figures: What is the mass of a cube of aluminum that is 4.0 cm on each edge? The density of aluminum is 2.7 g/cm3. Show all calculations leading to an answer.


Vcube= length-width-height
Vcube = 3.0cm.3.0cm.3.0cm=27cm3
2.7 g/cm3 = m/27cm3
m=2.7g/cm3.27cm3
m=73g

I agree

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To calculate the mass of the aluminum cube, we need to first determine the volume of the cube and then multiply it by the density of aluminum.

Step 1: Calculate the volume of the cube.
The volume of a cube is given by the formula V = length × width × height. Here, the length, width, and height of the cube are all equal to 4.0 cm. So, V = 4.0 cm × 4.0 cm × 4.0 cm = 64.0 cm³.

Step 2: Multiply the volume by the density to get the mass.
The density of aluminum is given as 2.7 g/cm³. Thus, the mass (m) can be calculated as m = density × volume = 2.7 g/cm³ × 64.0 cm³ = 172.8 g.

Therefore, the mass of the aluminum cube is 172.8 grams.

Now, let's check the significant figures:
The original measurements, 4.0 cm, have two significant figures.
The density, 2.7 g/cm³, has two significant figures.
The calculated volume, 64.0 cm³, has three significant figures.
Therefore, the mass should also be reported to two significant figures, giving us a final answer of 170 g.