Complete and balance this reaction: sulfuric acid reacts with barium chloride
H2SO4 + BaCl2 ---> BaSO4 + 2HCl
I just wanted to make sure I'm right
I see. I do all of the typing so you can check your values. How about us turning that around. You do the typing (show me what you have or tell me what you don't understand) and let me check your results.
You have the right equation, the right products, and it's balanced. Good work.
Deal , Thank you
To complete and balance the reaction between sulfuric acid (H2SO4) and barium chloride (BaCl2), we need to follow a few steps:
Step 1: Determine the chemical formula of the products.
Sulfuric acid is composed of a hydrogen ion (H+) and a sulfate ion (SO4^2-), while barium chloride is composed of a barium ion (Ba^2+) and chloride ions (Cl-).
Step 2: Write the reaction equation.
H2SO4 + BaCl2 -> BaSO4 + HCl
Step 3: Balance the equation.
To balance the equation, we need to ensure that the same number of atoms are present on both sides of the equation.
H2SO4 + BaCl2 -> BaSO4 + HCl
There are two hydrogen (H) atoms on the left and only one on the right. Multiply the HCl on the right side by 2 to balance the hydrogens.
H2SO4 + BaCl2 -> BaSO4 + 2HCl
There is one sulfur (S) atom on both sides, so no changes are necessary.
There are four oxygen (O) atoms on the left and only one on the right. Multiply the BaSO4 on the right side by 4 to balance the oxygens.
H2SO4 + BaCl2 -> 4BaSO4 + 2HCl
There is one barium (Ba) on the right and one on the left, so no changes are needed.
There are two chlorine (Cl) atoms on the left and only two on the right, so no changes are necessary.
The balanced equation is:
H2SO4 + BaCl2 -> 4BaSO4 + 2HCl