A cannon shoots a cannonball with a mass of 20 kg and a net force of 2000 N

a) label the three force pairs(HORIZONTAL ONLY)
b) What is the acceleration of the cannonball?
c) Does the cannon continue to move/ Explain why or why not. Specify which force will affect this.

a) The three force pairs acting on the cannonball in the horizontal direction are:

1. Applied force by the cannon on the cannonball: This force is exerted by the cannon on the cannonball to propel it forward.

2. Reaction force by the cannonball on the cannon: According to Newton's third law of motion, for every action, there is an equal and opposite reaction. So, the cannonball exerts a reaction force on the cannon, which is equal in magnitude but opposite in direction to the applied force.

3. Friction force: This force opposes the motion of the cannonball and acts in the opposite direction to its motion. It is caused by the interaction between the cannonball and the air or the surface it is moving on.

b) To determine the acceleration of the cannonball, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net external force acting on it and inversely proportional to its mass.

The formula for Newton's second law is:

acceleration = net force / mass

In this case, the net force acting on the cannonball is given as 2000 N, and the mass of the cannonball is 20 kg. Plugging these values into the formula:

acceleration = 2000 N / 20 kg = 100 m/s²

Therefore, the acceleration of the cannonball is 100 m/s².

c) No, the cannon does not continue to move. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. In this case, while the cannon exerts a force on the cannonball to propel it forward, the cannonball exerts an equal and opposite reaction force on the cannon. This reaction force acts in the opposite direction to the applied force, causing the cannon to recoil or move backward. The recoil force affects the motion of the cannon and eventually brings it to rest.