How many grams of KOH are needed to make 1.00L of a 1.3 molar (1.3 M) solution?
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I am not sure how to start this question, my teacher wants us to use conversion factors and write it out but I don't get how I am supposed to start it.
Start by asking yourself how many mols you need? Moles KOH you want = 1.00 L x (1.3 mols/L) = ? mols and that is 1.3 moles KOH.
Then 1.3 moles KOH x (56.1 grams KOH/mol KOH) = grams KOH you need for 1 L of 1.3M KOH.
To determine the number of grams of KOH needed to make a 1.3 M solution, you can follow these steps:
Step 1: Understand the given information:
- Molarity (M) is the number of moles of solute (in this case, KOH) per liter of solution.
- You have been given the molarity of the solution (1.3 M).
- The volume of the solution is also given (1.00 L).
Step 2: Set up the conversion:
- Start with the given molarity (1.3 M).
- Use the molar mass of KOH (56.11 g/mol) to convert from moles to grams.
Step 3: Solve the problem:
- Multiply the given molarity (1.3 moles/L) by the volume of the solution (1.00 L). This gives you the number of moles of KOH required.
- Multiply the moles of KOH by the molar mass of KOH (56.11 g/mol). This gives you the number of grams of KOH required.
Let's calculate the number of grams of KOH needed:
1.3 moles/L * 1.00 L = 1.3 moles
1.3 moles * 56.11 g/mol = 72.8 grams
Therefore, you would need 72.8 grams of KOH to make a 1.3 M solution with a volume of 1.00 L.