What is the pH of the resulting solution when 0.20 mole of NaF and 0.05 mole HCl are
added to 100 mL water?
The Ka for HF is 3.95x10^-4M
.........F^- + H^+ ==> HF
I.......0.2....0........0
add...........0.05........
C......-0.05..-0.05.....0.05
E......0.15....0.......0.05
Use the Henderson-Hasselbalch and calculate pH.