How many moles of H2 and N2 can be formed by the decomposition of 0.250 mol of ammonia, NH3?

Is it 0.250*3mol H2=0.75

0.25*1mol N2=0.25

Am I correct?

I think your error is caused by not balancing the equation. ALWAYS start with a balanced equation.

2NH3 ==> N2 + 3H2
0.250mols NH3 x (1 mol N2/2 mol NH3) = 0.250 x 1/2 = ? mols N2

0.250 mols NH3 x (3 mols H2/2 mols NH3) = 0.250 x 3/2 = ? mols H2

To determine the number of moles of H2 and N2 formed by the decomposition of 0.250 mol of NH3, we need to consider the balanced chemical equation for the reaction.

The balanced equation is:

2NH3 -> 3H2 + N2

From the equation, we can see that for every 2 moles of NH3, 3 moles of H2 and 1 mole of N2 are formed.

Given that there is 0.250 mol of NH3, we can calculate the amount of H2 and N2 produced as follows:

H2: (0.250 mol NH3) x (3 mol H2 / 2 mol NH3) = 0.375 mol H2

N2: (0.250 mol NH3) x (1 mol N2 / 2 mol NH3) = 0.125 mol N2

So, the correct amounts are 0.375 mol of H2 and 0.125 mol of N2.

To determine how many moles of H2 and N2 can be formed by the decomposition of ammonia (NH3), we need to consider the balanced chemical equation for the reaction.

The balanced equation for the decomposition of ammonia is:

2NH3 -> 3H2 + N2

This equation tells us that 2 moles of NH3 react to produce 3 moles of H2 and 1 mole of N2.

Given that you have 0.250 mol of NH3, we can determine the moles of H2 and N2 formed as follows:

1) H2:
Using the ratio from the balanced equation, 2 mol NH3 reacts to produce 3 mol H2. Therefore, for every 2 moles of NH3, we will have 3 moles of H2.
So, the moles of H2 can be calculated as:
(0.250 mol NH3) * (3 mol H2 / 2 mol NH3) = 0.375 mol H2

2) N2:
Using the ratio from the balanced equation, 2 mol NH3 reacts to produce 1 mol N2. Therefore, for every 2 moles of NH3, we will have 1 mole of N2.
So, the moles of N2 can be calculated as:
(0.250 mol NH3) * (1 mol N2 / 2 mol NH3) = 0.125 mol N2

Therefore, you are correct that the decomposition of 0.250 mol of NH3 will produce approximately 0.375 mol of H2 and 0.125 mol of N2.