Two rectangles have an area of 81 square inches.Name two possible perimeters for the rectangles.
you want to find factors of 81. They are
1,81
3,27
9,9
Each choice gives a different perimeter.
181 and 327
To find two possible perimeters for the rectangles, we first need to determine the dimensions of the rectangles by finding two factors of 81.
The factors of 81 are:
1, 3, 9, 27, 81
Let's consider the possible dimensions of the rectangles using these factors:
1. Dimensions: length = 1 inch, width = 81 inches
Perimeter = 2(length + width) = 2(1 + 81) = 2 * 82 = 164 inches
2. Dimensions: length = 3 inches, width = 27 inches
Perimeter = 2(length + width) = 2(3 + 27) = 2 * 30 = 60 inches
So, two possible perimeters for the rectangles are 164 inches and 60 inches.
To determine the possible perimeters of the rectangles, we need to consider the different combinations of length and width that can yield an area of 81 square inches.
Let's start by finding all possible pairs of factors of 81. The factors of 81 are 1, 3, 9, 27, and 81.
Now, we can assign the factors to the length and width of the rectangles in various ways. For example:
Pair 1:
Length = 1 inch, Width = 81 inches
Perimeter = 2(Length + Width) = 2(1 + 81) = 2(82) = 164 inches
Pair 2:
Length = 3 inches, Width = 27 inches
Perimeter = 2(Length + Width) = 2(3 + 27) = 2(30) = 60 inches
It's important to note that since the question asks for two possible perimeters, there are other combinations of factors that can be assigned to the rectangles' dimensions. However, these are just two examples.