car moves at a constant velocity up an inclined plane making an angle of 28degrees with the horizontal. The coefficient of friction is 0.387. The force exerted by the engine on the car is 588N.
Calculate the Following
A.weight of the car
B.frictional force acting on the car
Component of force acting down the incline
F1 = mg sin(θ)
Normal component of weight (affects friction)
N = mg cos(θ)
Frictional force
Fr = μkN
Force exerted by engine to overcome gravity and friction
F= Fr + F1
To calculate the weight of the car and the frictional force acting on it, we can use some basic physics principles and equations.
A. The weight of the car can be calculated using the formula:
Weight = mass * gravity
Since we're given the force exerted by the engine (588N), we can use this as the net force acting on the car. At a constant velocity, the net force is equal to 0. The force of gravity acting vertically downwards is balanced by the force exerted by the engine in the opposite direction:
Force of gravity - Force exerted by the engine = 0
Weight - 588N = 0
Therefore, the weight of the car is equal to 588N.
B. The frictional force acting on the car can be calculated using the formula:
Frictional force = coefficient of friction * normal force
The normal force is the force exerted by the surface perpendicular to the inclined plane. It can be calculated using the formula:
Normal force = weight * cos(angle)
In this case, the angle of the inclined plane is 28 degrees. Since we've already calculated the weight of the car as 588N, we can substitute these values into the equation:
Normal force = 588N * cos(28 degrees)
Once we calculate the normal force, we can then calculate the frictional force using the coefficient of friction and the normal force:
Frictional force = 0.387 * normal force
By substituting the calculated value of the normal force into the equation, we can find the frictional force acting on the car.