1) C2H2O4(aq) = H+ (aq) + C2HO4- (aq); Keq = 6.5E-2
2) C2O42- (aq) + H+ (aq) = C2HO4- (aq); Keq = 1.64E+4
then what is the equilibrium constant for the following reaction: C2H2O4(aq) = 2H+ (aq) + C2O42- (aq)?
Keq = 1070
Keq = 227
Keq = 2.21E-4
Keq = 3.96E-6
Keq = 6.30E-3
Add eqn 1 to the REVERSE of eqn 2.
k1 = Keq for eqn 1.
k2 = Keq for eqn 2.
k' = keq for the REVERSE of eqn 2 = 1/k2
When you add equilibrium equations you multiply the k values so
k new rxn = k1*k' = k1*(1/k2) = ?
To find the equilibrium constant for the reaction C2H2O4(aq) = 2H+ (aq) + C2O42- (aq), you can use the equilibrium constant expression, which is given by the product of the concentrations of the products divided by the product of the concentrations of the reactants, each raised to their stoichiometric coefficients in the balanced equation.
Given the following equilibrium reactions and their respective equilibrium constants:
1) C2H2O4(aq) = H+ (aq) + C2HO4- (aq); Keq = 6.5E-2
2) C2O42- (aq) + H+ (aq) = C2HO4- (aq); Keq = 1.64E+4
Let's consider the overall reaction:
C2H2O4(aq) = 2H+ (aq) + C2O42- (aq)
Since this reaction is not directly given, we can use the given reactions to construct it by combining the two reactions above.
By adding the two reactions, we can cancel out the C2HO4- (aq) species:
C2H2O4(aq) + C2O42- (aq) + 2H+ (aq) = 2H+ (aq) + C2HO4- (aq)
Simplifying the equation, we get:
C2H2O4(aq) + C2O42- (aq) = H+ (aq) + C2HO4- (aq)
Now we can compare this equation with the given reaction:
C2H2O4(aq) = H+ (aq) + C2HO4- (aq)
Based on this comparison, we can conclude that the equilibrium constant for the overall reaction is the product of the equilibrium constants for the two given reactions.
Therefore, the equilibrium constant for the overall reaction C2H2O4(aq) = 2H+ (aq) + C2O42- (aq) is:
Keq = (Keq1) * (Keq2)
Keq = (6.5E-2) * (1.64E+4)
Keq ≈ 1.06E+3 (rounded to three significant figures)
Therefore, the correct answer is:
Keq = 1070.
To find the equilibrium constant for the given reaction:
C2H2O4(aq) = 2H+ (aq) + C2O42- (aq)
We can use the principle of equilibrium constants:
Keq = Keq1 × Keq2
where Keq1 is the equilibrium constant for the forward reaction and Keq2 is the equilibrium constant for the reverse reaction.
To obtain Keq1, we can refer to the first equation:
C2H2O4(aq) = H+ (aq) + C2HO4- (aq); Keq1 = 6.5E-2
To obtain Keq2, we need to reverse the second equation:
C2HO4- (aq) = C2O42- (aq) + H+ (aq); Keq2 = 1/Keq2_reverse
where Keq2_reverse is the equilibrium constant for the reverse reaction.
Now, let's calculate Keq2_reverse:
Keq2_reverse = 1/Keq2 = 1/(1.64E+4) = 6.097E-5
Finally, we can calculate Keq using the equation:
Keq = Keq1 × Keq2_reverse
Keq = (6.5E-2) × (6.097E-5) ≈ 3.96E-6
Therefore, the equilibrium constant for the given reaction: C2H2O4(aq) = 2H+ (aq) + C2O42- (aq) is approximately Keq = 3.96E-6.