3x+4=19

X=5
5+C/9=31
C=-324

11=2Y-15
Y=13

Bink/Tanne/ Kasey/ Twinkle/Megan -- Please use the same name for your posts.

My name is Roderick and my nickname is Bink..I go to Forrest city at high school. Who is tanne and Megan?????

Just needed a problem checked

To solve the equation 3x + 4 = 19, we need to isolate the variable x.

1. Start by subtracting 4 from both sides of the equation:
3x + 4 - 4 = 19 - 4
3x = 15

2. Then, divide both sides of the equation by 3 to solve for x:
3x/3 = 15/3
x = 5

Therefore, the solution is x = 5.

To solve the equation 5 + C/9 = 31, we need to isolate the variable C.

1. Start by subtracting 5 from both sides of the equation:
5 + C/9 - 5 = 31 - 5
C/9 = 26

2. Multiply both sides of the equation by 9 to solve for C:
(C/9) * 9 = 26 * 9
C = 234

Therefore, the solution is C = 234.

To solve the equation 11 = 2Y - 15, we need to isolate the variable Y.

1. Start by adding 15 to both sides of the equation:
11 + 15 = 2Y - 15 + 15
26 = 2Y

2. Then, divide both sides of the equation by 2 to solve for Y:
26/2 = 2Y/2
Y = 13

Therefore, the solution is Y = 13.