How do I calculate the average Z molar mass, 1/n (Summation) of n*M given this data: (alternate equation: MZ=Summation N*M^3/Summation N*M^2)
(Ave molar mass, mass of sample):
(7.5,9.6) , (12.5,8.7), (17.5, 8.9), (22.5, 5.6), (27.5, 3.1), (32.5,1.7)
mili moles for repective numbers: 1.3,.7,.51,.25,.11,.052 TOTAL: 2.92
I don't know what numbers to sum
I don't understand the question. Perhaps another tutor will.
thanks for taking a look! :)
To calculate the average Z molar mass using the given data, you will need to follow these steps:
1. Firstly, let's identify the values we need to sum in the equations provided. For our alternate equation MZ = Summation (N * M^3) / Summation (N * M^2), we need to sum N * M^3 and N * M^2 separately.
2. Calculate the values for N * M^3 and N * M^2 for each data point. N represents the moles, and M represents the molar mass.
- For the data point (7.5, 9.6), N * M^3 = 1.3 * (9.6^3) and N * M^2 = 1.3 * (9.6^2)
- For the data point (12.5, 8.7), N * M^3 = 0.7 * (8.7^3) and N * M^2 = 0.7 * (8.7^2)
- For the data point (17.5, 8.9), N * M^3 = 0.51 * (8.9^3) and N * M^2 = 0.51 * (8.9^2)
- For the data point (22.5, 5.6), N * M^3 = 0.25 * (5.6^3) and N * M^2 = 0.25 * (5.6^2)
- For the data point (27.5, 3.1), N * M^3 = 0.11 * (3.1^3) and N * M^2 = 0.11 * (3.1^2)
- For the data point (32.5, 1.7), N * M^3 = 0.052 * (1.7^3) and N * M^2 = 0.052 * (1.7^2)
3. Calculate the sums for N * M^3 and N * M^2 separately.
- Sum of (N * M^3) = Sum of (1.3 * (9.6^3), 0.7 * (8.7^3), 0.51 * (8.9^3), 0.25 * (5.6^3), 0.11 * (3.1^3), 0.052 * (1.7^3))
- Sum of (N * M^2) = Sum of (1.3 * (9.6^2), 0.7 * (8.7^2), 0.51 * (8.9^2), 0.25 * (5.6^2), 0.11 * (3.1^2), 0.052 * (1.7^2))
4. Finally, divide the sum of (N * M^3) by the sum of (N * M^2) to get the average Z molar mass.
- Average Z molar mass = Sum of (N * M^3) / Sum of (N * M^2)
By following these steps, you should be able to calculate the average Z molar mass using the given data.